MATLAB: 2d function in 3d

2dfunction

i need to show this function y = x^2 in 3d in matlab

Best Answer

Try this:

x = [1;1] * linspace(-4, 4, 25) ;
y = x.^2;
figure(1)
surf(x, y, [zeros(size(x(1,:))); 5*ones(size(x(1,:)))], 'EdgeColor','b')
grid on
view(-75, 45)

EDIT — Added plot.

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MATLAB: Slice along a curved plane

After some digging, problem solved. I figured I should share the solution here.

The index terms (xd,yd,zd) need to be 2-D.

[yd,zd]=meshgrid(lat,depth);

[xd,zd]=meshgrid(lon,depth);

slice(x,y,z,c,xd,yd,zd);

MATLAB: Plot a curve as a vertical 3D surface in MATLAB

Try this:

x = linspace(0, 2*pi, 50);                      % Independent Variable

y = sin(x);                                     % Dependent Variable

z = [ones(size(x)); zeros(size(x))];            % ‘Z’ Matrix

figure(1)
surf([x; x], [y; y], z)
grid on
axis equal

Also, if you want more ‘levels’ in the z-direction:

x = linspace(0, 2*pi, 50);                              % Independent Variable
y = sin(x);                                             % Dependent Variable
z = [(1:-0.2:0)'*ones(size(x))];                        % ‘Z’ Matrix
figure(1)
surf(repmat(x,size(z,1),1), repmat(y,size(z,1),1), z)
grid on
axis equal

The ‘(1:-0.2:0)’ in the z calculation sets the number of ‘levels’ and values of the ‘levels’. Experiment with it to get the result you want.

NOTE — This requires x and y to be row vectors.

EDIT — Added plot image.

Best Answer

Related Solutions

MATLAB: Slice along a curved plane

MATLAB: Plot a curve as a vertical 3D surface in MATLAB

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