MATLAB: (1/2) – (3-j4)/(5-j8)

engineeringmaths

I need to get the answer to this in the form x+jy

Best Answer

Calculating it is straightforward. Multiply the numerator and denominator of the complex part of the expression by the complex conjugate of the denominator:

fc = (3-4j)*(5+8j)/((5-8j)*(5+8j))
f = 1/2 - fc

Only the real part of ‘f’ is then subtracted from ‘1/2’.

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MATLAB: How would i type in the fraction in the polynomial to find the real and complex roots

I expanded your function in the Symbolic Math Toolbox, and got the coefficient vector:

cfx = [1     -0.5       -2       -1        0       -3];
fxroots = roots(cfx)

produces:

fxroots =
       1.9710e+000 +             i
      -1.1131e+000 +654.8187e-003i
      -1.1131e+000 -654.8187e-003i
     377.6052e-003 +877.5463e-003i
     377.6052e-003 -877.5463e-003i

Note that the first root is real. It should be simply 1.9710, but since the others are complex, it is listed with a complex part for consistency. You could do all of this in the Symbolic Math Toolbox of course, but since you didn’t mention that you have access to it, I do not assume you do.

MATLAB: How p(:,j) differs from p(j,:)

 p=[1 2;3 4;5 6]

check this

p(:,2)
p(3,:)

p(:,2) means all lines, column number 2, p(3,:) means all columns, line number 3

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Related Solutions

MATLAB: How would i type in the fraction in the polynomial to find the real and complex roots

MATLAB: How p(:,j) differs from p(j,:)

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