MATLAB: [1 0 1 1 0 1 1 0] to [10 11 01 10]

matrix manipulationvector

I need to transform 8 numbers into 4 like the title, how could i do that?

Best Answer

V = [1 0 1 1 0 1 1 0];
one_way = V(1:2:end) * 10 + V(2:2:end)
another_way = reshape(V, 2, []).'

Related Solutions

MATLAB: Storing integers from a cell in a variable

Much more efficient than cellfun:

>> C = {'(4,4)';'(3,4)';'(2,4)';'(1,4)';'(0,4)';'(-1,4)';'(-2,4)'};
>> V = sscanf([C{:}],'(%f,%f)');
>> X = V(1:2:end)
X =
   4
   3
   2
   1
   0
  -1
  -2
>> Y = V(2:2:end)
Y =
   4
   4
   4
   4
   4
   4
   4

MATLAB: Find the precision of a value

No doubt there will be disagreements over what it means for floating point numbers, but here is one solution which provides the least unexpected output by converting to string, converting the last non-zero digit to 1 and the rest to 0. I do not claim that it is fast, but it does seem to be reasonably robust.

function p = getprecision(x)
f = 14-9*isa(x,'single'); % double/single = 14/5 decimal places.
s = sprintf('%.*e',f,x);
v = [f+2:-1:3,1];
s(v) = '0'+diff([0,cumsum(s(v)~='0')>0]);
p = str2double(s);
end

and tested:

>> getprecision(5.34)
ans =  0.010000
>> getprecision(5)
ans =  1
>> getprecision(53400)
ans =  100

Notes:

keep in mind that 5.34 and 0.01 do not really exist in binary floating point numbers. See Adam's comment.
'%g' is an obvious choice, but is actually more complicated because it can return fixed point values with trailing zeros.

Best Answer

Related Solutions

MATLAB: Storing integers from a cell in a variable

MATLAB: Find the precision of a value

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