Top singular value of large random matrices: concentration results

linear algebrapr.probabilityrandom matrices

Let $A$ be a $n\times m$ random matrix, whose elements $a_{ij}$ are independent standard Gaussian random variables.
I am interested in the case $n=\alpha N\,$, $\,m=(1-\alpha)N$ for $\alpha\in(0,1)$ fixed and $N\to\infty$.

Denote by $\sigma_\max(N)$ the largest singular value of $\frac{1}{\sqrt{N}}A$, that is the square root of the largest eigenvalue of the symmetric square matrix $\frac{1}{N}AA^T$.

I am looking for a concentration result of type:
$$ \mathbb P(\sigma_\max(N)\geq K) \,\leq\, e^{-N F(K)}$$
for constants $K$ in a suitable range, a suitable function $F(K)$, and $N$ sufficiently large. I do not need $F$ to be optimal.

In the square matrix case ($\alpha=\frac{1}{2}$), an analogous result holds true for the top eigenvalue $\lambda_\max(N)$ of the symmetric matrix $\frac{A+A^T}{\sqrt{2N}}$. But I could not find anything about large deviations of the top singular value in the rectangular case. Any reference or suggestion is very welcome.

Best Answer

This largest singular value is the norm of the matrix. You can use a net argument to show that there is a $C$ so that $$\mathbb{P}(\| A \|_{op} \geq C\sqrt{N}(\sqrt{\alpha} + \sqrt{1 - \alpha} + t)) \leq 2 e^{-Nt^2}$$ for all $\alpha, t$. For a reference, this appears as Theorem 4.4.5 in Vershynin's High Dimensional Probability book.

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