Sum of Two nth Powers in Finite Fields – Number Theory Insights

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Let $q$ be a prime power, let $n$ be a positive integer and let $\mathbb{F}_q$ be the finite field of cardinality $q$. I have some computational evidence that the set $$\{x^n+(-1)^nay^n:x,y\in\mathbb{F}_q\}$$ is the whole of $\mathbb{F}_q$, unless $q$ is small (with respect to $n$).

This does make sense because if, for instance, $q-1=n$, then the set
$\{ x^n+(-1)^nay^n:x,y\in\mathbb{F}_q \}$ only consists of $\{0,1,a,1+a\}$ because each element of $\mathbb{F}_q$ raised to the $n$ equals either $0$ or $1$.

Can anyone justify the computational evidence?

Best Answer

Yes, this is true, and is proved e.g. as Corollary 3 of Small's "Diagonal equations over large finite fields" (Can. J. Math. 1984).

Small actually gives explicit bounds on how large $q$ needs to be in terms of $n$ — in particular the equation $ax^n+by^n$ generates all of $\mathbb{F}_q$ whenever $a,b\in\mathbb{F}_q\setminus\{0\}$ and $q>(\delta-1)^4$, where $\delta=(n,q-1)$.