I know my question is a bit vague, sorry for this.
Let $k$ be a field of characteristic zero. Consider the Grothendieck ring of varieties over $k$, usually denoted by $K_0(Var_k)$. This is generated by isomorphism classes of varieties over $k$ modulo the relations [X]=[Y]+[X-Y] whenever $Y$ is a closed subvariety of $X$. People usually refer to [X] as the "naive" motive of $X$.
On the other hand, one has Voevodsky's "true" motives $DM_{gm}(k)$ (not as true as we would like to, I know !) and to any variety $X$ we can attach an object $M(X)$in $DM_{gm}(k)$.
Why is this $M(X)$ more serious than the naive one? That is, can you give some examples of properties that cannot be read at the level of $K_0(Var_k)$ but that one sees when working in $DM_{gm}(k)$?
Best Answer
I think the presence of Voevodsky's category of (mixed) motives is a red herring here. Let me briefly explain why I think that, and then say why any "real" notion of motives (say, pure Chow motives, as in Vivek Shende's comment) or, I guess, Voevodsky's motives, are much more serious than the so-called naive motives.
The (partially conjectural) motivic philosophy says we should functorially associate to each variety $X$ a motive, which is an object in some Abelian category with a "weight" (which is just a number) associated to any simple object; any reasonable cohomology theory (e.g. Betti cohomology) is supposed to factor through this functor. If $X$ is a smooth projective variety, this motive is naturally supposed to be a direct sum of (semi-simple) pieces in each weight. A cohomological realization functor applied to the weight $i$ piece should be the degree $i$ cohomology of the original variety. For a general variety, one does not get a semi-simple object, but rather some iterated extension of pieces of large weight by pieces of smaller weight. The associated filtration gives the weight filtration on passing to some cohomological realization. Proving that something like this is true is pretty far out of reach.
But anyway, the picture is supposed to be something like $$\text{Varieties}\to \text{Mixed Motives}\overset{ss}{\to} \text{Pure Motives}$$ where the second map is semi-simplification w.r.t. the weight filtration. We don't know what the middle term in this diagram is, but there is a perfectly good term on the right hand side, given by Grothendieck's Chow Motives; Voevodsky's category is a candidate for the derived category of the middle object. There are several other candidates as well, I guess.
Now, we can also send any variety $X$ to its class $[X]$ in the Grothendieck ring of varieties, $K_0(\text{Var})$. This remembers some of the "motivic" information of $X$; in particular, there is a map $K_0(\text{Var})\to K_0(\text{Chow Motives}_\mathbb{Q})$ so that if $X$ is smooth and projective, the image of $[X]$ under this map will be the class of its associated Chow motive in the K-group of Chow motives. If $X$ is not smooth and projective, it will be (conjecturally) the class of the semi-simplification of its (mixed) motive with respect to the weight filtration (because $K_0$, by definition, forgets all extension information). So in particular, this is the "motivic" manifestation of Dan Petersen's answer: the Grothendieck ring of varieties forgets the weight filtration.
But aside from this, I think "mixedness" is not really important for understanding this question--the Grothendieck ring of varieties forgets a lot more than the weight filtration!
Because smooth projective varieties are "cohomologically pure," the Grothendieck ring of varieties does "remember," say, the Hodge structures on their cohomology groups. Namely, one can take a class in $K_0(\text{Var})$ and send it to its Euler characteristic in the $K$-theory of rational Hodge structures; because of purity, one can pick out its individual cohomology groups. The main issue is that the Grothendieck ring of varieties forgets morphisms! Namely, one can recover the map $$H^i: \text{Smooth Varieties} \mapsto H^i(-, \mathbb{Q})$$ sending a smooth projective variety to its $i$-th cohomology group, but not the functor. And if you can get much algebraic geometry done without using any of the functorial properties of cohomology, I'd be very impressed.
Let me just remark that the map $K_0(\text{Var})\to K_0(\text{Chow Motives}_\mathbb{Q})$ is quite mysterious, and does forget some information. For example, it is not injective--given two isogenous elliptic curves $E_1, E_2$ over $\mathbb{C}$, the class $[E_1]-[E_2]$ is not zero in $K_0(\text{Var})$ (by results of Larsen-Lunts, for example), but its image in $K_0(\text{Chow Motives}_\mathbb{Q})$ is zero. On the other hand, I see no reason for the map to be surjective either (for example, I have no idea how to hit a random Chow Motive of pure weight).