Suppose $G$ is a finite $p$-group with odd $p$. Is it true, that $Aut(G)$ is nilpotent iff $G$ is cyclic?
When $G$ is cyclic, $Aut(G)$ is indeed abelian and thus nilpotent.
However, I do not know how to prove the statement that if $Aut(G)$ is nilpotent, then $G$ is cyclic. Nor do I possess any counterexamples.
Any help will be appreciated.
Best Answer
The order of the automorphism group of ${\tt SmallGroup}(31,729)$ is $3^9$ and hence nilpotent.