Wave equation: travelling solutions

partial differential equationswave equation

I know that $f(x-ct)$, $g(x+ct)$ and $f(x-ct)+g(x+ct)$ are all solutions of the wave equation
$$
\frac{\partial u}{\partial t^2}=c^2\frac{\partial^2 u}{\partial x^2}.
$$

This is easily shown using the chain rule. How do I interpret this as left and right travelling functions? I'm having a hard time getting the picture of what's happening.

Best Answer

Let $f:\mathbb{R} \to \mathbb{R}$ and define $F :\mathbb{R}^2 \to \mathbb{R}$ as $F(x,t)=f(x-ct)$. It will solve the equation. Pick your favourite point, for example $(0,0)$. If you watch the evolution of this point in time, you will see that its coordinates will satisfy $x-ct=0$, i.e. $x=ct$, so it will travel to the right. The argument is similar for the $x+ct$ combination.

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