It is given that the leading digit of every number in the division structure is nonzero.
I am not getting how to find all the missing digits given only one digit from the quotient and given that the reminder is $0$.
Any help on how to proceed will be helpful.
Source: Homework Assignment.
This is what I got.
Best Answer
Probably the most powerful piece of information comes from the 7 in the quotient. If you look down from there, you see that 7 times the three-digit divisor gives a three-digit number. That means that the divisor has to be between 100 and 142 (since 7x143 = 1001), and so its first digit must be 1.
From that, you can see that a couple of the products are 4 digits, so they must be multiplying the divisor by 8 or 9 - but even 142x9 = 1278, so the first of those four digits must be a 1. You can then use that to gain more information about the divisor, and also about what digits could go in each place.