The universal cover covers any connected cover

algebraic-topologycovering-spacesgeneral-topology

The Wikipedia page about covering spaces asserts that:

The universal cover (of the space $X$) covers any connected cover (of the space $X$).

I'm not able to find a proof of this result. Any idea how to find it or how to prove it?

Here the definition of universal cover is just that of a covering being simply connected. Moreover, a part from connectedness of the other cover there is no other hypothesis.

Best Answer

Sofie Verbeek's answer is perfect, but let me go back to the definition of a universal covering space. There are two different approaches: Some (perhaps most) authors define a universal covering $p : E \to X$ of a connected space $X$ to be one such that $E$ is simply connected, other authors define it by the property that it covers any covering $p' : E' \to X$ with a connected $E'$.

In my opinion the second definition is the better one because it is explains the name. If you accept this point of view, then it is a theorem that a simply connected covering of a connected and locally path connected $X$ is a universal covering.

A nice reference is Chapter 2 Section 5 of

Spanier, Edwin H. Algebraic topology. Vol. 55. No. 1. Springer Science & Business Media, 1989.

It contains a number of interesting results and examples (e.g. of a non-simply connected universal covering space of a of a connected and locally path connected space).