The collection of unions of finite disjoint collections of sets in a semiring is closed under finite unions and finite intersections.

measure-theoryreal-analysis

Define a semiring to be a collection $S$ of subsets of $X$ such that if $A$, $B \in S$, then $A \cap B \in S$, and there is a finite disjoint collection $\{C_k\}$ of sets in $S$ such that $A – B = \bigcup_{k=1}^n C_k$.

Define $S'$ to be the collection of unions of finite disjoint collections of sets in $S$, how to prove that $S'$ is closed with respect to the finite unions and finite intersections.

(please do not assume $S'$ is closed under relative complements, cause later I need to use the above property to prove $S'$ is closed under relative complements.)

Can anyone help me on this please?

Best Answer

Let $A$ and $B$ be sets in $S'$. Then there are finite disjoint collections $\{A_i\}_{i=1}^n$ and $\{B_j\}_{j=1}^m$of sets in $S$, such that $A= \bigcup_{i=1}^n A_i$ and $B= \bigcup_{j=1}^m B_j$.

It is easy to see that $\{A_i\cap B_j\}_{i,j=1}^n$ is a finite disjoint collection of sets in $S$. So, $$ A\cap B= \bigcup_{i,j=1}^n (A_i\cap B_j) \in S' \tag{1}$$

Now note that $$A \cup B_1 = \left (\bigcup_{i=1}^n A_i \right )\cup B_1 = \left (\bigcup_{i=1}^n (A_i \setminus B_1) \right )\cup B_1 $$

For each $i$, $1\leqslant i \leqslant n$ there is a finite disjoint collection $\{D_{i,k}\}_{k=1}^{n_i}$ of set in $S$ such that $A_i \setminus B_1= \bigcup_{k=1}^{n_i}D_{i,k}$. Since $\{A_i\}_{i=1}^n$ is a finite disjoint collection of sets in $S$, we can conclude that the collection $\{ D_{i,k} : 1 \leqslant i \leqslant n, 1 \leqslant k \leqslant n_i \} \cup \{B_1\} $ is a finite disjoint collection of sets in $S$. So, we have $$ A \cup B_1 = \left (\bigcup_{i=1}^n (A_i \setminus B_1) \right )\cup B_1 = \left (\bigcup_{i=1}^n \bigcup_{k=1}^{n_i} D_{i,k} \right )\cup B_1 \in S' $$ So, we have that $ A \cup B_1 \in S'$. By finite induction, we have that $$ A\cup B = A \cup \left (\bigcup_{j=1}^m B_j \right ) =( ( ( (A\cup B_1)\cup B_2) \cdots )\cup B_m) \in S' \tag{2} $$

From $(1)$ and $(2)$, by finite induction, we have that $S'$ is closed with respect to the finite unions and finite intersections.

Remark: Since the question is about semirings, we must be careful about the term "finite intersection". If we take an empty collection of sets in $S'$, the intersection of such empty family is, by definition, $X$ which may not be in $S$ nor in $S'$. So, we understand here "finite intersection" as being the intersection of a non-empty family of sets in $S'$.