Consider the space $S^{n-1}$ in $\mathbb{R}^n$. Put $N= (0,0,\dots, 0,1), S = (0,0, \dots, 0,-1)$ and consider the stereographic projections
$$\phi_N: U_N:= S^{n-1}\setminus \{N\} \to \mathbb{R}^{n-1}$$
$$\phi_S: U_S:= S^{n-1}\setminus \{S\} \to \mathbb{R}^{n-1}$$
Consider the atlas $\mathcal{A} = \{(U_N, \phi_N), (U_S, \phi_S)\}$.
Equip the space $S^{n-1}$ with the natural topology
$$\mathcal{T}:= \{V \subseteq S^{n-1}\mid \phi_N(U_N \cap V), \phi_S(U_S\cap V) \mathrm{\ are \ open \ sets \ in \ \mathbb{R}^{n-1}}\}$$
Is the space $\mathcal{T}$ Hausdorff?
My attempt:
I showed that every two points can be separated by disjoint open sets, except the points $N$ and $S$. How would I show that these poins can be separated by disjoint open sets? My guess is that we have to select two specific open sets.
Best Answer
Take the northern hemisphere $\mathcal{N}=\{(x_1,\ldots,x_n)\in S^{n-1}\,|\,x_n>0\}$ and the southern hemisphere $\mathcal{S}=\{(x_1,\ldots,x_n)\in S^{n-1}\,|\,x_n<0\}$. Then: