Show that $|1-z| \leq |z|+1$

absolute valuecomplex numbersinequality

According to wolfram alpha, this inequality holds:

$$|1-z| \leq |z|+1,$$

however, I haven't been able to figure out why. The reverse inequality (or at least the way I've applied it) gives me a lower bound on $|1-z|$ instead of an upper bound. I've tried using the regular triangular inequality and adding and subtracting like $|1-z+z-1| \leq |1-z| + |z-1|$ but I'm still stuck.

Best Answer

$$|1-z|\leqslant|1|+|-z|=1+|z|.$$

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