Ring theory conventions – Zero ring, local homomorphisms

algebraic-geometrycommutative-algebraconventionringed-spacesschemes

Just wondering about conventions dealing with the zero ring and the zero scheme.

  1. Does the category of schemes have an inital object?
  2. Is the zero ring considered local?
  3. For the purposes of scheme theory, is a map of sheaves that induces on stalks a map of the form $\mathcal{O}_{X,P}\to 0$ considered a "local" homomorphism on stalks?

https://en.wikipedia.org/wiki/Zero_ring
Wikipedia says that the zero ring is not local.

I am wondering how to square this with certain conventions in scheme theory. If $0$ is the zero ring, then conventionally (say in Hartshorne Chapter II, exercise 2.6) the category of schemes has $Spec(0)$ for an initial object; whose underlying space is $\emptyset$ and whose associated sheaf is the constant sheaf at zero. The direct image of this sheaf along the canonical map $\emptyset \to X$ would be, again, the constant zero sheaf, so the canonical natural transformation $\mathcal{O_X}\to 0$ would send every stalk to zero. It seems like this shouldn't count as a map of locally ringed spaces.

Best Answer

The empty scheme is initial in the category of schemes, and the zero ring is not a local ring, since it does not have a unique maximal ideal (it does not have any maximal ideal!). There is no special convention needed here--this all just follows from the general definitions.

In particular, there is no issue with what the unique map out of the empty scheme does on stalks. If $X$ and $Y$ are locally ringed spaces, then a morphism $X\to Y$ is a continuous map $f:X\to Y$ together with a morphism of sheaves of rings $\mathcal{O}_Y\to f_*\mathcal{O}_X$ such that for each $x\in X$ the induced map on stalks $\mathcal{O}_{Y,f(x)}\to \mathcal{O}_{X,x}$ is a local homomorphism. When $X$ is empty, there are no points $x\in X$ at which to check this condition, and so it holds vacuously.