The Cox Ingersoll Ross is given in the form:
$$dr_t = a(b-r_t)dt + \sigma \sqrt{r_t}dW_t$$
According to Wikipedia, the expected value of it i.e $E[r_t|r_0]$ is
$$r_0e^{-at} + b(1-e^{-at})$$
but I don't really understand how it's derived. Can you give some hints?
Best Answer
Hint
Remark that
$$\mathbb E[r_t]=\mathbb E[r_0]-a \int_0^t\mathbb E[r_s]\,\mathrm ds+abt$$
and use Gronwall inequality.