Prove that if an entire function has uncountably many zeroes then it must be constant

complex-analysisentire-functions

I am solving assignment questions of complex analysis which might not be discussed due to pendamic and I was unable to solve this particular question.

Let f be an entire function that has uncountably many zeroes . Prove that it is constant.

I was unable to get an idea on which result to use although I am good in complex analysis. So, It's my humble request to you tp kindly guide me.

I thought of $\prod_{r_i varies in\in \mathbb{R}} (z-r_i) $ , and I don't know why it must be constant.

Best Answer

Hint: If for each $z\in S\subset\Bbb C$ we find $r_z>0$ such that the open ball $B_{r_z}(z)$contains no point of $S$ other than $z$, then the balls $B_{r_z/2}(z)$ are pairwise disjoint and each contains a point with rational coordinates.

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