Motivation for Defining Measurable Functions

measurable-functionsmeasure-theoryterminology

I have just started Measure Theory from Bartle, The Elements of Integration and Lebesgue Measure, where he defines Measurable Functions as:
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What is the motivation for this? How is it related/equivalent to the more standard way of defining measurable functions by considering elements as pre-images?

Best Answer

If $X$ a set and $\mathcal X$ is a $\sigma$-algebra on it then for a function $f:X\to\mathbb R$ the following statements are equivalent:

  • $f$ is Borel-measurable
  • For every $B\in\mathcal B(\mathbb R)$ we have $f^{-1}(B)\in\mathcal X$
  • For every $\alpha\in\mathbb R$ we have $\{x\in X\mid f(x)>\alpha\}\in\mathcal X$

(where $\mathcal B(\mathbb R)$ denotes the Borel $\sigma$-algebra on $\mathbb R$ i.e. the smallest $\sigma$-algebra that contains all open subsets of $\mathbb R$)

Note that here $\{x\in X\mid f(x)>\alpha\}=f^{-1}((\alpha,\infty))$ while $(\alpha,\infty)\in\mathcal B(\mathbb R)$ so actually the condition under the second bullet implies the condition under the third bullet directly.

Conversely the condition under the third bullet is enough to prove that the condition under the second bullet is satisfied. This because it can be proved that:$$\sigma(\{(\alpha,\infty)\mid\alpha\in\mathbb R\})=\mathcal B(\mathbb R)$$ and secondly in general:$$f^{-1}(\sigma(\mathcal V))=\sigma(f^{-1}(\mathcal V))$$for every collection $\mathcal V\subseteq\mathcal P(\mathbb R)$ (so for instance for $\mathcal V:=\{(\alpha,\infty)\mid\alpha\in\mathbb R\}$).

Which one (second or third bullet) to use as definition is a matter of choice.