Why is R Semisimple Ring if Every R-Module is Semisimple?

modulessemi-simple-rings

I'm reading An introduction to homological algebra of Rotman, but the proposition 4.5 of the section 4.1 Semisimple rings states this:

The following conditions on a ring $R$ are equivalent.

  • $R$ is semisimple.

  • Every left (or right) $R$-module $M$ is a semisimple module.

  • Every left (or right) $R$-module $M$ is injective.

  • Every short exact sequence of left (or right) $R$-modules splits.

  • Every left (or right) $R$-module $M$ is projective.

And the proof of the first point to the second doesn't look very clear. This is the proof the book has:

Since $R$ is semisimple, it is semisimple as a module over itself;
hence, every free left $R$-module is a semisimple module
. Now $M$ is a
quotient of a free module, by Theorem $2.35$, and so Corollary $4.2$ gives
$M$ semisimple.

I don't understand why the part in boldface is true. Can anyone explain to me the hence part?

Best Answer

By definition, a semisimple ring is a ring which is semisimple as a left module over itself. A free left $R$-module is a left module (isomorphic to a module) of the form $\bigoplus_{A} R$ for some index set $A$. Moreover, it is true that if $M_i$ is a collection of semisimple modules, then $\bigoplus_{i\in I}M_i$ is also semisimple. Putting all this together implies the result.

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