Why do you change the index of a power series when you differentiate it?
$$\sum_{n=0}^\infty \frac{d}{dx}(-x)^n=\sum_{n=1}^\infty n(-x)^{n-1}(-1)$$
A slow, dumbed-down explanation would be appreciated.
calculuspower seriessequences-and-series
Why do you change the index of a power series when you differentiate it?
$$\sum_{n=0}^\infty \frac{d}{dx}(-x)^n=\sum_{n=1}^\infty n(-x)^{n-1}(-1)$$
A slow, dumbed-down explanation would be appreciated.
Best Answer
Notice what happens if we don't change the index, we end up with
$$\frac d{dx}x^n=nx^{n-1}$$
But when we sum it up from $n=0$ to $\infty$, the $n=0$ case ends up as $0$. And so it is removed from the sum. Also, you might want to check your result, it doesn't seem quite right.