[Math] When does an inner product induce a norm

inner-productslinear algebranormed-spaces

When we consider a vector space $V$ over some field $F$, I know that when the $F=\mathbb{R}$ or $ =\mathbb{C}$, by setting $\|x\|=\left\langle{x,x}\right\rangle^\frac{1}{2}$ we get a norm. However, since the inner product is a function with its image in $F$, what happens if we consider any $V$ over the rational numbers? For example, if we take $\mathbb{Q}^2$ over $\mathbb{Q}$ with the dot product, then $v=(1,1)$ has norm $\sqrt{2}$, which is not rational. How can one obtain a norm from a given inner product in such cases?

Best Answer

An ordered field where $a^2+b^2$ is always a square is called a Pythagorean field. As you observe, not every ordered field is Pythagorean, but each ordered field has a Pythagorean extension. If you really want $L^2$-norms you could always extend your ground field to a Pythagorean extension field.

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