[Math] What does it mean to be going 40 mph (or 64 kph, etc.) at a given moment

calculusintuition

I was coming back from my Driver's Education class, and something mathsy really stuck out to me.

One of the essential properties of a car is its current speed. Or speed at a current time. For example, at a given point in time in my drive, I could be traveling 40 mph. But what does that mean?

From my basic algebra classes, I've learned that speed = distance/time. So if I travel ten miles in half an hour, my average speed would be $20$ mph ($\frac{10 mi}{25 h}$).

But instantaneous velocity…you aren't measuring average speed for a given amount of time. You're measuring instantaneous speed over an…instantaneous amount of time.

That would be something like (miles) / (time), where time = $0$? Isn't that infinite?

And perhaps, in a difference of time = $0$, then I'd be travelling $0$ miles. So would I be said to be going $0$ mph at an instantaneous moment in time? I'd like to be able to tell that to any cops pull me over for "speeding"!

But then if miles = $0$ and time = $0$, then you have $\frac00$?

This is all rather confusing. What does it mean to be going $40$ mph at a given moment in time, exactly?

I've heard this explained using this strange art called "calculus" before, and it's all gone over my head. Can anyone explain this using terms I (a High School Algebra and Geometry and Driving student) will understand?

(I figured that my problem had numbers in it, and therefore has to do with Maths.)

Best Answer

I think there is a very clear meaning in the physical world: If, at some moment, you were going 40 mph, if you were to stop de/accelerating and just hold that velocity, you would cover 40 miles in 1 hour.

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