[Math] Using the pigeonhole principle to prove there is at least two groups of people whose age sums are the same.

combinatoricspigeonhole-principle

In a room there are 10 people, none of whom are older than 100 (ages are given in whole numbers only) but each of whom is at least 1 year old. Prove that one can always find two groups of people (possibly intersection, but different) the sums of whose ages are the same.

I know we have to use the pigeon hole principle. But I don't know how to find the pigeons and pigeonholes. Can someone help me out?

Best Answer

Hint: what is the maximum sum of all the ages in the room? How many subsets are there of people in the room?