the sequence $\{a_n\}$ is defined by recursively as $a_0=3$ and $a_n=6a_{n-1}+2$ for all $n\geq0$
Use the iteration to make an educated guess at an explicit formula for a sequence
My attempt: $a_0=3$
then $a_1=6a_0+2=20$
$a_1=122$
$a_2=734$
adding all the terms implies
3+20+122+734+…..+(upto n terms)
I am stuck form here find an explicit formula for a sequenc
Best Answer
Study the sequence $a_n - a_{n-1}$. It goes like $17, 102, 612$ etc. Do you see that this is a geometric series, with first term $17$ and constant ratio $6$?
Hence, $a_n- a_{n-1} = 17 \cdot 6^n$, you could say? Now figure out the general formula for $a_n$, and see if the additions work out. I'l give the answer in this "hidden hint":