Two cards are drawn one after another (without replacement) from a well shuffled pack of $52$ playing cards. Show the probability of getting or not getting a face card by drawing a tree diagram.
My attempt
Is this the complete solution or something is missing?
Best Answer
Your tree diagram looking correct. Once cross check your answer by solving question without tree diagram.
Output from tree diagram.
Case 1 -
Probability of getting at least one face card (including both are face cards) -
$\frac{12}{52} \times \frac{11}{51} + \frac{12}{52} \times \frac{40}{51} + \frac{40}{52} \times \frac{12}{51}$
Case 2 -
Probability of getting no face card -
$\frac{40}{52} \times \frac{39}{51}$