if $\tan \theta = \sqrt{63}$ and $\cos \theta$ is negative, find $\sin \theta$.
So since $\tan \theta$ is positive and $\cos \theta$ is negative, it lies in the $3$rd quadrant. So $\sin$ is negative, but I don't know how to find $\sin \theta$, please guide me… Thank you.
Best Answer
HINT
Remember $\tan \theta$ is just $\frac{\sin \theta}{\cos \theta}$. Here you have $\tan \theta = \frac{\sqrt{63}}{1}$ Now, draw a triangle with the sides as $\sqrt{63}$ and $1$. Now you should be able to find $\sin \theta$ and adjust the signs.
FURTHER HINT