[Math] Triangle inequality: How to prove Minkowski inequality

analysisfunctional-analysisreal-analysis

It is not clear for me how the triangle inequality is used here:

enter image description here

And by the triangle inequality (1.3)
$$\left(\sum\limits_{i=1}^n |\xi_i+\eta_i|^2\right)^{1/2} \le
\left(\sum\limits_{i=1}^n |\xi_i|^2\right)^{1/2} + \left(\sum\limits_{i=1}^n |\eta_i|^2\right)^{1/2}.$$

Especially because the absolute value on the left side is squared and we have taken the square root of all the summation on the left side.could anyone clarify this for me?

Edit:

I think I should have corrected my above question "How to prove Minkowski inequality"?

Thanks!

Best Answer

Hint. By squaring both sides we obtain the equivalent inequality $$\sum_{i=1}^n |\xi_i+\eta_i|^2\leq \left(\left(\sum_{i=1}^n |\xi_i|^2\right)^{1/2}+\left(\sum_{i=1}^n |\eta_i|^2\right)^{1/2}\right)^2$$ that is $$\sum_{i=1}^n |\xi_i|^2+\sum_{i=1}^n |\eta_i|^2+2\sum_{i=1}^n |\xi_i||\eta_i|\leq \sum_{i=1}^n |\xi_i|^2+\sum_{i=1}^n |\eta_i|^2+2\sqrt{\sum_{i=1}^n |\xi_i|^2}\sqrt{\sum_{i=1}^n |\eta_i|^2}.$$ Can you take it from here?

Related Question