Calculate the coordinates of the point on the curve $y = 2 \sqrt{x}$ that is closest to the point $(2,0)$.
What I did was I found the slope. Then I set the slope equal to the derivative. From then on, I don't know what to do. I came to a dead end.
[Math] The point on the curve $y = 2 \sqrt{x}$ that is closest to the point $(2,0)$
calculus
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Best Answer
The distance function can be written as
$$d(x) = (x-2)^2+4 x = x^2+4$$
Where is this a minimum?