[Math] the intuition behind the definition of the differential of a function

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What is the intuition behind the definition of a differential of a function in differential geometry? i.e. $$df(p)(v_{p}) =v_{p} (f)(p) $$ where $v_{p} \in T_{p} M$ is a vector in the tangent space to the point $p\ M$.

Is it just that the notion of an infinitesimal change in a function is not mathematically rigorous (in the "traditional" sense that it's presented in elementary calculus). So in order to make the notion mathematically rigorous we note that a quantity that captures the notion of an infinitesimal change in a function should itself be a function of all the possible infinitesimal changes of the point that the function is evaluated at, i.e. it should be a function of the all possible tangent vectors in the vector space tangent to that point (as such quantities describe the possible directions that a function can pass through a point and all the possible "speeds"). In this sense the differential change in the function as it passes through the point in a given direction should be equal to the directional derivative of the function along the particular vector describing that direction?!

Best Answer

The most classical answer is probably: $df_p$ is the best linear approximation of $f$ at $p$, in a sense that can be made precise.

Personally I often like to think of it in the following way: while $f$ transforms positions, the differential of $f$ transforms velocities (or: while $f$ transforms points, $df$ transforms tangent vectors.)

u**strong text**

More precisely: let $t \mapsto x(t)$ be a curve in $M$ through $p$ at $t=0$. The image of this curve in $N$ is $t \mapsto y(t) = f(x(t))$. Let $v = x'(0) \in T_{p}M$ and $w = y'(0) \in T_{f(p)}N$. Then $w = df_p(v)$.

In short: $$\frac{d}{dt}_{|t=0}f(x(t)) = df_{x_0} (x'(0))$$

I find this interpretation of the differential useful both conceptually and also very often practically.