Full question: the difference between two numbers a and b is 1, and the product of the numbers is 9. Show that there are two possible pairs of values which satisfy these condictions and evaluate the numbers
This is not to do with complex numbers so you cannot have negative roots if using quadratic equation (which i seem to keep getting.)
Best Answer
you will get $$x-y=1$$ and $$xy=9$$ if $$x\geq y$$ thus we have the quadratic equation $$(1+y)y=9$$ and $$y^2+y-9=0$$ can you solve this?