Suppose a box contains 4 balls numbered 1,2,3,4. From this box, 2 balls are randomly drawn without replacements. Let X denote the larger of the two numbers on the balls selected. Find the probablity distribution table of X and draw it's bar chart.
Distribution table of X:
$$\begin{array}{|c|c|c|c|c|}\hline X & 1 & 2 & 3 & 4 \\ \hline f(x) & 0 & 1/6 & 2/6 & 3/6 \\\hline\end{array}$$
And I'm thinking these are the only options for the selection we have:
$\{(1,2),(1,3),(1,4),(2,3),(2,4),(3,4)\}$
I would appreciate any form of help. And if I messed something up please feel free to fix it or let me know! I want to figure this out but with your help because I'm learning and I'm unsure.
Best Answer
You are correct that 1 must have probability 0. The 6 possibilities you list are equally likely. There is only one with 2 as the maximum and so this has probability $\frac{1}{6}$. Over to you for the others!