If we have the following equation of a paraboloid:
$z=4-x^2-y^2$ and we have the region in space bounded by this paraboloid from above and by the $xy$-plane from below; we want to find the volume of this region using the spherical coordinates in the following orders; $d\rho\,d\phi\,d\theta$,
$d\phi\,d\rho\,d\theta$.
In the first order if we follow a ray from the origin, it will cut the surface which is the one of the paraboloid but we will end up with a second degree polynomial equation…
Best Answer
From:
$$x^2+y^2=4-z$$
we obtain:
$$\rho^2 \sin^2\phi=4-\rho \cos \phi\implies\rho^2 \sin^2\phi+\rho \cos \phi-4=0$$
and thus
$$\rho=\frac{-cos \phi\pm \sqrt{\cos^2 \phi+16\sin^2 \phi}}{2\sin^2 \phi}\implies \rho=\frac{-cos \phi+ \sqrt{\cos^2 \phi+16\sin^2 \phi}}{2\sin^2 \phi}>0$$