$dr=(r\cos\theta +r\sin\theta)d\theta$ In my book this is under separation of variables then i tried to factor out r and divide both sides then integrate both sides but where can i find my $C_1$? I just got $\ln(r)=\sin\theta-\cos\theta$
[Math] Solving the differential equation $dr=(r\cos\theta +r\sin\theta)d\theta$
calculusintegrationordinary differential equations
Best Answer
When taking an indefinite integral you add a constant of integration
$$\int\frac{1}{r}dr=\int(cos(\theta)+sin(\theta))d\theta$$
$$ln|r|=sin(\theta)-cos(\theta)+C$$