This probably seems like a very basic question but it has been along time since I did any trigonometry…
I am trying to calculate the sides of an obtuse triangle given the 3 angles:
$$\angle A = 38.6642, \angle B = 136.56, \angle C = 4.775$$
and the side $a = 10.18$ (opposite $\angle A$).
I have tried the Sine Rule:
$$\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}$$
thus yielding
$c = \sin(C) \cdot \dfrac{a}{\sin(A)}$ , but with the triangle I have, that gives me $-12.3948…$
What have I misunderstood? How can I calculate the sides?
Best Answer
I was using MATLAB and the sin() function requires radians. To convert degrees to radians the degtorad() function can be used.