I'm trying to solve a calculus of variations geodesics problem using Lagrange Multipliers, showing that the geodesics of a sphere are the so-called great circles. I am using a constrained Lagrangian
$$\int_{a}^{b}\dot{x}^2+\dot{y}^2+\dot{z}^2+\lambda(t)G(x(t),y(t),z(t))dt$$
where G(x,y,z) is the sphere $$x^2+y^2+z^2 = 1$$
Computing the Euler-Lagrange equations, I get the three equations:
$$\ddot{\vec{r}}=\frac{\lambda(t)}{2}\nabla G$$
and the constraint remains: $$\sqrt{x^2+y^2+z^2}=1\ \text{ or equally }\ x^2+y^2+z^2=1$$
Applied to the circle, we find:
$$\ddot{\mathbf{r}}=\lambda(t)\mathbf{r}$$
So now we have four equations, an unknown lambda function, and 3 variables. How do I determine lambda and simplify it enough to solve in Mathematica? This is very unfamiliar material for me, so help is appreciated.
Thanks
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$\textbf{Edit: expanding on the solution provided by Qmechanic}$
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Differentiating the constraint twice yields the familiar
$$\mathbf{\ddot{r}}\cdot\hat{\mathbf{r}}=-\frac{v^2}{r}$$
And taking the dot product of the EL equations with $\mathbf{\hat{r}}$ and substituting yields
$$-\frac{v^2}{r^2}=\lambda(t)$$
Substituting this back into the original equation for $\lambda(t)$, we find that
$$\ddot{\mathbf{r}}=-\frac{v^2}{r}\mathbf{\hat{r}}$$
This allows an infinite number of geodesics, but choosing the parameterization that leaves v constant, this simplifies to
$$\mathbf{\ddot{r}}=-\mathbf{r}$$
which can be solved for the Cartesian coordinates:
$$\begin{matrix}
x=C_1 \sin (t)+C_2 \cos (t) \\
y=C_2 \sin (t)+C_4 \cos (t) \\
z=C_3 \sin (t)+C_6 \cos (t) \\
\end{matrix}$$
Which, with appropriate initial conditions, forms a great circle between the two points.
Best Answer
Hints:
Deduce from the equations of motion (i.e. the EL equations) that the specific angular momentum ${\bf L}:={\bf r}\times\dot{\bf r}$ is a constant of motion.
Deduce that position ${\bf r}$ and velocity $\dot{\bf r}$ are both perpendicular to ${\bf L}$.
Deduce that the orbit lies in a plane that goes through the origin.
The intersection of the orbit plane with the sphere is hence a great circle.