A rectangular piece of paper,10cm by 24cm, is folded so that a pair of diagonally opposite corners coincide. Find the length of the crease.
x^2=(24-x)^2+10^2
[Math] Solve Pythagoras problem solving
pythagorean triples
pythagorean triples
A rectangular piece of paper,10cm by 24cm, is folded so that a pair of diagonally opposite corners coincide. Find the length of the crease.
x^2=(24-x)^2+10^2
Best Answer
Hint : Try To fold Paper, and You'll get it
You can then continue with @ir7 's answer
Note : The Diagram is not upto the scale