[Math] Solution Verification: Maximum number of edges, given 8 vertices

discrete mathematicsgraph theory

Suppose a simple graph G has 8 vertices. What is the maximum number of
edges that the graph G can have?

The formula for this I believe is

n(n-1) / 2

where n = number of vertices.

8(8-1) / 2 = 28. Therefore a simple graph with 8 vertices can have a maximum of 28 edges. Is this correct?

Best Answer

Yes, it is. The maximum number of edges is simply the number of pairs of distinct vertices; if there are $n$ vertices, this is

$$\binom{n}2=\frac{n!}{2!(n-2)!}=\frac{n(n-1)}2\;.$$