$\sqrt{125}-\sqrt5$ simplify it.
I thought it would be $\sqrt {5\cdot5\cdot5}-\sqrt 5$ which would be the square root of 25 which is 5 but it is not.
Can you show how to simplify this?
algebra-precalculusarithmeticsquare-numbers
$\sqrt{125}-\sqrt5$ simplify it.
I thought it would be $\sqrt {5\cdot5\cdot5}-\sqrt 5$ which would be the square root of 25 which is 5 but it is not.
Can you show how to simplify this?
Best Answer
$\sqrt{125}-\sqrt{5}=\sqrt{5\times 25}-\sqrt{5}=\sqrt{25}\sqrt{5}-\sqrt{5}=5\sqrt{5}-\sqrt{5}=4\sqrt{5}$