[Math] Simplify $\frac{\sqrt{24}}{8}$

fractionsradicalssquare-numbers

The question I have been given is to simplify as much as possible: $\frac{\sqrt {24}}{8}$. I know the answer is $\frac{\sqrt 6}{4}$

(Note I am in a beginner math course, so go easy on me.)

My first thought was to divide to get: $\frac{\sqrt {12}}{4}$ and then again: $\frac{\sqrt 3}{1}$. However, I realized this was wrong. So I tried $\frac{\sqrt {24}}{2\times\sqrt 4}$ which would make the denominator equal to 4, which is right. So I thought I could do that to the top too, but I couldn't. I feel like I'm on the right track but not really there. Can someone help me figure out how to solve questions like these?

Best Answer

You could square the fraction, then simplify, then take the square root. $$\frac{\sqrt{24}^2}{8^2}=\frac{24}{64}=\frac{6}{16}$$

Taking the square root of both sides leaves the desired answer. $$\frac{\sqrt{6}}{\sqrt{16}}=\frac{\sqrt{6}}{4}$$

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