Problem is to simplify this boolean expression:
$(a+b+c')(a'b'+c)$
I expanded it out and simplified to get to $a'b'c' + c(a+b)$ but that doesn't reduce the number of literals. Tried everything I could think of but I must be missing something…
boolean-algebra
Problem is to simplify this boolean expression:
$(a+b+c')(a'b'+c)$
I expanded it out and simplified to get to $a'b'c' + c(a+b)$ but that doesn't reduce the number of literals. Tried everything I could think of but I must be missing something…
Best Answer
How is this?
Found using Logic Friday 1.