Note: I am using log base 10 and I am trying to rewrite the equation using exponents instead of logs.
Here is what I have and I am wondering if I did it correctly (if not how am I suspose to solve this question):
$$\log(A^2) = B$$
$$2\log(A) = \log(B)$$
$$\log(B)/\log(A) = 2$$
$$10^2$$
Best Answer
Your second line doesn't look correct. The rule is $\log(A^n)=n\cdot\log(A)$, so:
$$ \log(A^2)=B \\ 2\log(A)=B \\ \log(A)=\frac{1}{2}B \\ A=10^{\frac{1}{2}B} $$