I have the following question that I have to solve however I cannot achieve.
Let $R$ be a ring with $1$ and suppose $R$ has no zero divisors. Show that the only idempotents in $R$ are $0$ and $1$.
Please help me to solve this question.
Your prompt reply will be greatly appreciated.
Thanks in advance.
Best Answer
Suppose $e$ is idempotent. Then $e^2=e$, so $e^2-e=0$. Trying factoring and see what happens, using the fact that there are no zero divisors.