Show that the four points, $(5, 8), (7, 5), (3, 5)$ and $(5, 2)$ are the vertices of a rhombus.
I tried solving it, by finding out the distances by using the formula $\sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$
I found all of them but two sides are equal and other two are not. As far as I know, rhombus has all sides equal…but mine does not match! Help please 🙂
Best Answer
Hint: Here are the points on graph paper.