Show that if $A$ is any square matrix such that $A^n = 0$ for some positive integer $n$, then $A$ is not invertible.
I'm not sure if my proof is good enough, or enough "work" as my teacher put it after my last test.
This is what I have:
$$A^n = 0$$
or $A$ to be invertible,
$$A^n A^{-n} = I$$
Then:
$$A^{n} \cdot A^{n} =0 \cdot A^{-n} $$
$$I \neq 0$$
this is not true, so $A$ is not invertible.
Best Answer
Hint:If $A$ is nilpotent operator, then its only eigenvalue is zero.