What would be the example of a function for which a Secant Method fails but Bisection Method converges (to the root). In particular, if we are checking the interval $[a,b]$, then starting points for the Secant Method are $a$ and $b$.
[Math] Secant and Bisection Method
numerical methods
Best Answer
Try to find a continuously differentiable function with the following properties:
The first point ensures that the bisection methods converges. Whereas if $f'(\xi)=0$, the secant method can fail. See these lecture notes (page 101) for an example.