I'm looking to schedule 16 players to play a round robin tournament with each other such that there are 4 players at each table. I'd like for each player to play with each other player exactly once over the course of 5 rounds.
I just took a look at this post: Rearrangement of groups such that no two members meet again , and I was wondering if anyone knows if the case n=m=4 has been solved, and if so what that solution is.
Best Answer
This should work:
Please verify. (Each row is a table and the 4 tables for each round is enclosed by a square).