I need to re-arrange the following equation to make $d$ the subject [i.e., solve for $d$]:
$$a = \sqrt{\frac{d}{be}}.$$
The square root part is really confusing me, any help would be much appreciated.
algebra-precalculus
I need to re-arrange the following equation to make $d$ the subject [i.e., solve for $d$]:
$$a = \sqrt{\frac{d}{be}}.$$
The square root part is really confusing me, any help would be much appreciated.
Best Answer
Ok. Squaring both sides you obtain $$a^{2} = \frac{d}{be} \Longrightarrow d = (be) \times a^{2}$$