[Math] Re-arranging an equation with a square root

algebra-precalculus

I need to re-arrange the following equation to make $d$ the subject [i.e., solve for $d$]:

$$a = \sqrt{\frac{d}{be}}.$$

The square root part is really confusing me, any help would be much appreciated.

Best Answer

Ok. Squaring both sides you obtain $$a^{2} = \frac{d}{be} \Longrightarrow d = (be) \times a^{2}$$

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