Given the series $$\sum_{n=0}^{\infty}(-1)^nx^{2^n}$$
determine the radius of convergence, and what can we say when $x=R$ and $-R$?
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Is it a power series? Power series should have the form of $$\sum_{n=0}^{\infty}a_nx^n$$
but the given series does not match this form. If not a power series, why can we say about its radius of convergence? -
By the ratio test, I get that this series converges when $|x|<1$, diverges when $|x|>1$, so $R=1$, is that right?
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When $x=1$ or $-1$, series both becomes $$\sum_{n=0}^{\infty}(-1)^n,$$
then obviously, series diverges. Right?
Best Answer
(1): see the comments.
(2): the radius of convergence $\rho$ of $\sum a_nx^n$ is defined to be:
$$ \rho:=\frac{1}{\alpha} $$
where
$$ \alpha = \lim_{n\rightarrow \infty} \sup \sqrt[n]{|a_n|} $$.
Here we have:
$|a_n| = 1$ if $n$ is a power of 2, $|a_n|=0$ otherwise. Thus $\rho=1$.