- Suppose there are three measurable spaces
$(\Omega, \mathbb{F})$, $(S_i,
\mathbb{S}_i), i=1,2$, and two
measurable mappings $f_i: \Omega
\rightarrow S_i, i=1,2$. Is the
mapping $f$ defined as
$f(\omega):=(f_1(\omega),
f_2(\omega))$ a measurable mapping
from $(\Omega, \mathbb{F})$ to
$(\prod_{i=1}^2 S_i, \prod_{i=1}^2
\mathbb{S}_i)$, where $\prod_{i=1}^2
\mathbb{S}_i$ is the product sigma
algebra of $\mathbb{S}_i, i=1,2$? - Suppose there are four measurable spaces
$(\Omega_i, \mathbb{F}_i), i=1,2$,
$(S_i, \mathbb{S}_i), i=1,2$, and
two measurable mappings $f_i:
\Omega_i \rightarrow S_i, i=1,2$. Is
the mapping $f$ defined as
$f(\omega_1,
\omega_2):=(f_1(\omega_1),
f_2(\omega_2))$ a measurable mapping
from $(\prod_{i=1}^2 \Omega_i,
\prod_{i=1}^2 \mathbb{F}_i)$ to
$(\prod_{i=1}^2 S_i, \prod_{i=1}^2
\mathbb{S}_i)$? - In Part 1 and Part 2, conversely, if
$f$ is a measurable mapping, will
$f_i, i=1,2$ be measurable mappings? - Can the statements in Part 1,2 and
3 be generalized to any
collection of $(S_i, \mathbb{S}_i) i
\in I$ and $(\Omega_i, \mathbb{F}_i)
i \in I$?
Thanks and regards! Are there some websites or books that address these questions?
Best Answer
The product $\sigma$-algebra on $S_1\times S_2$ is generated by sets of the form $A\times B$, with $A\in \mathbb{S}_1$ and $B\in\mathbb{S}_2$. The function $f$ is measurable if and only if the inverse image of a measurable set is measurable, and it suffices to check that the inverse image of a measurable set in a specific generating set for the $\sigma$-algebra is measurable. So it suffices to see if $f^{-1}(A\times B)$, with $A$ and $B$ as above, is measurable.
If $x\in f^{-1}(A\times B)$, then $f(x)\in A\times B$, so $f_1(x)\in A$ and $f_2(x)\in B$. Thus, $x\in f_1^{-1}(A)\cap f_2^{-1}(B)$. Conversely, if $x\in f_1^{-1}(A)\cap f_2^{-1}(B)$, then $f(x)\in A\times B$. So $f^{-1}(A\times B) = f_1^{-1}(A)\cap f_2^{-1}(B)$. Is this set in $\mathbb{F}$?
Same idea: what is $f^{-1}(A\times B)$? $(x,y)\in f^{-1}(A\times B)$ if and only if $x\in f_1^{-1}(A)$ and $y\in f_2^{-1}(B)$, so $f^{-1}(A\times B) = f_1^{-1}(A)\times f_2^{-1}(B)$. Is this set in the product $\sigma$-algebra $\mathbb{F}_1\times\mathbb{F}_2$?
Are the projection maps $\pi_i\colon (S_1\times S_2,\,\mathbb{S}_1\times\mathbb{S}_2)$ measurable? Is the composition of measurable functions measurable? What are $\pi_i\circ f$?
I'll leave 4 to you.