Let us consider two real numbers $x$ and $y$. How can we prove value of $xy$ is greatest when $x=y$ given the condition $x+y=$ constant?
I have already found a proof, but I am not entirely happy with it yet.
algebra-precalculusinequality
Let us consider two real numbers $x$ and $y$. How can we prove value of $xy$ is greatest when $x=y$ given the condition $x+y=$ constant?
I have already found a proof, but I am not entirely happy with it yet.
Best Answer
First prove that $$ xy = \frac{1}{4} \left( (x + y)^2 - (x - y)^2 \right)$$ How can you maximize $xy$ given this?