ABCS is a trapezoid, and EQ and FP are bisectors of these trapezoid arms.
I would like to prove that angle CQB is equal to angle APD.
I tried to show similarity between triangles CQB and APD, because both of them are isosceles. If I could show that similarity exists, then angle CQB could equal to angle APD. However, I don't know how to show that these triangles are similar.
Best Answer
You have to prove that minor base of trapezoid and vertices of isosceles triangles are on the same circle and major base and vertices of isosceles triangles are on another circle. Thus the angles in green are equal and the angle in pink are equal so the sum of green and pink are equal and finally the two angles of the isosceles triangles are equal